use the subtitution method to solve.
x^2 + 2y = 9
x - y + 3 = 0
can someone help me?

Question

anonymous · Answer

from equation (2):
y=x+3 -> (3)
substitute for y with x+3, you get:
$$x^2+2(x+3)=9 \implies x^2+2x-3=0$$
factorize it to get:
$$(x+3)(x-1)=0 \implies x=-3, x=1$$
substitute for each value of x in equation 3$$x=-3 \implies y=-3+3=0$$
$$x=1 \implies y=1+3=4$$

anonymous · Answer

therefore the problem has two solutions:
$$(x,y)=(-3,0)    ,  (x,y)=(1,4)$$

anonymous · Answer

Ok I get it. My answer was really close to that. Thank you!

anonymous · Answer

you're welcome :).. feel free to fan me ;)