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lim x-> 0 sin5x/sin4x
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Apply l'Hopital's rule, and it comes out extremely cleanly.
You can use l'Hopital's rule whenever you have a limit which comes out to be 0/0 or infinity/infinity and has the form " lim f(x)/g(x) ".
ok so in this case you have to use l'hopitals rule which will getyou sin(5x) der is 5cos(5x) sin(4x) der is 4cos(4x) so you will end up wit limit as n - > 0 of 5cos(0)/4cos(0) = 5/4
sweet!!!!!!!!!!!!!!!!!!!! ya I got 5/4, man this is really cool
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