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Mathematics 14 Online
OpenStudy (anonymous):

Anyone here good with linear algebra?

OpenStudy (anonymous):

Yes, what's your question?

OpenStudy (anonymous):

Suppose A is an nxn matrix, whose determinant is not equal to zero and which satisfies the following condition: A^2=A. Prove that A must be equal to In, where I is the identity matrix. Cite any theorems/ definitions used. It'd be a great help if I could get a little "push" or hint.

OpenStudy (anonymous):

Are you taking a college course or middle school? If it's a college course, then you're further ahead than I am.

OpenStudy (anonymous):

Sorry, high school*

OpenStudy (anonymous):

Jzzkc, linear algebra isn't the same thing as the algebra of linear equations. :P

OpenStudy (anonymous):

College course :(

OpenStudy (anonymous):

Det =/= 0 <=> There Exists a nxn matrix B s.t AB = I = BA.

OpenStudy (anonymous):

=> A^2 = AA = A => AAB = AB => AI = I => A = I

OpenStudy (anonymous):

How did you get A62 = AA to become A?

OpenStudy (anonymous):

A^2 = A. The matrix satisfies this condition.

OpenStudy (anonymous):

and A^2 = AA.

OpenStudy (anonymous):

Are you also famliar with span and null space?

OpenStudy (anonymous):

Yes I suppose so.

OpenStudy (anonymous):

How did you get from the A^2=AA=A step to the step AAB=AB?

OpenStudy (anonymous):

I multiplied B, the matrix that has the property AB = I = AB. The Inverse of A. You could multiply it like this => BAA = BA too if you want.

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