Mathematics
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OpenStudy (anonymous):
where do i go from,
15(5x^2-1)-(x-2)
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OpenStudy (anonymous):
What are you trying to do?
OpenStudy (anonymous):
factor the polynomial.
OpenStudy (anonymous):
egh. I'd start by getting it into the standard polynomial form
OpenStudy (anonymous):
the original is, 75x^3-150x^2-15x+30
OpenStudy (anonymous):
Ok, so factor a 15 out of everything.
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OpenStudy (anonymous):
well i do factor by grouping
OpenStudy (anonymous):
I'd start by getting smaller numbers.
OpenStudy (anonymous):
well thats why i broke it up into 75x^3-150x^2
abd -15x+30
OpenStudy (anonymous):
and*
OpenStudy (anonymous):
\[75x^3-150x^2-15x+30\]
\[= 15(5x^3 - 10x^2 - x + 2)\]
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OpenStudy (anonymous):
Then regrouping and pulling a 5x from the first two terms you should have something nice.
OpenStudy (anonymous):
that way you would pull out a 75 and get 75x^2(x-2)15(x-2)
OpenStudy (anonymous):
so then its (75x^2-15) and (x-2)
thenn 15(5x^2+1)(x-2)
OpenStudy (anonymous):
\[15(5x^3 - 10x^2 - x + 2) \]
\[= 15[5x(x-2) -(x-2)]\]
\[= 15(5x-1)(x-2)\]
OpenStudy (anonymous):
whoops i meant -1.
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OpenStudy (anonymous):
so i basically had the right answer
right?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
Mine should be
\[15[5x^2(x−2)−(x−2)]\]
\[=15(5x^2-1)(x-2)\]
OpenStudy (anonymous):
gotcha
OpenStudy (anonymous):
alright i will be back in a few with some more