Question

when do you use the inverse when doing logs?

Answer 1

log is the inverse of exponents; and exponents are the inverse of logs.

What is your question regarding?

Answer 2

i dont understand how to do them at all. how would you graph y=3log(base5)x. how would you go about that

Answer 3

Hey amistre can you please help me with 2 antiderivative questions after you are done here?

Answer 4

Since y = 3 log5(x) is the same as:

y = log5(x^3) we can more easily graph its inverse and then "flip" the graph about the y=x line.

Answer 5

sure thing...

Answer 6

you got a question posted we can go to :)

Answer 7

did you get the second equation from switching the x and ys and solving for y?

Answer 8

did you see my question

Answer 9

yeah, but I messed it up in my head the first time :)

Answer 10

meet me there when you can help me

Answer 11

will do...

Answer 12

mini: log graphs can be hard to do without a calulator; so we can rewrite it to a more familiar form... do you agree?

Answer 13

but how do you make it in the other form?

Answer 14

im there

Answer 15

y = 3 log5(x) ; divide by 3

y/3 = log5(x) ; take the 5^ of each side

5^(y/3) = 5^(log5(x)) ; 5^(log5) cancel each other out.

5^(y/3) = x

Do you agree? Are you familiar with the rules for logs?

Answer 16

i understand how you did that. when is that that you go about switching the x and y to solve?

Answer 17

When it makes the graphing easier you can modify it. All you are doing is solving for x instead of y, so keep aware of that

Answer 18

Would you agree that 5^(y/3) is easier to plot for and solve than log5(x) ? :)

Answer 19

yess

Answer 20

how do you do for example logbase8 4096=4

Answer 21

Do you mean:

log8(4096) = 4 ??

Answer 22

yes

Answer 23

is it just 8^4=4096

Answer 24

that is what is known as an identity. one side equals the other.

Lets take for example:

logB(x) = y this means that B^y=x

We can take your equation for instance:

log8(4096) = 4 means:

8^4 = 4096, we can test that by either pen and paper , or calculator :)

Answer 25

35^log 35^x

Answer 26

35^log35 = 1 and we are left with "x"

Answer 27

can you do the inverse of y=log1/4 x out step by step please?

Answer 28

y=ln 6x

Answer 29

is that log base (1/4)?

Answer 30

i understand that one now but how do you do the second one?

Answer 31

y = ln(6x) correct?

Answer 32

just y= ln 6x not base 6x

Answer 33

"ln" is just a special way they write log to the base "e"

Answer 34

y = ln(6x)

e^y = e^ln(6x)

e^y = 6x

(e^y)/6 = x

Answer 35

how about y= ln (x+2)

Answer 36

e^y = x+2

e^y -2 = x

Answer 37

so for the graph of y=log8 x-2
you would do
8^y=x-2
and then fill in values for y such as 0
which would be
1=x-2
x=3?