Question

Solve the differential equation(antiderivatives calculus 2)
f(x)=
12x^3+ 6x^2-
7 with initial condition f(
1)=
4

Answer 1

Hi Saif, you here?

Answer 2

yea i am here

Answer 3

its college calculus 2, antiderivatives are killin me. SO confusing

Answer 4

Confused. There is no differential as written. Does "dx" multiply the polynomial?

Answer 5

what do you mean?

Answer 6

Are you asking us to just integrate/ find the antiderivative of the function f(x)?

Answer 7

You want to the integral and its anchor at (1,4) right?

Answer 8

yea i think so
I thought it was just asking the antiderivative with that condition

Answer 9

F(x)= (12/4)x^4+ (6/3)x^3 -7x + C

F(x) = 3x^4 +2x^3 -7x +C

solve for F(1) = 4 :)

Answer 10

you are using big F(x), its giving you f'(x), wouldnt the notation change?

Answer 11

its not the same convention as a general antiderivative

Answer 12

naming is naming, I just did it to be flamboyant :)

Answer 13

ok so the totation would be f(x) correct and then you find f(1)

Answer 14

i mean you find C

Answer 15

We find the "antiderivative" of the function to find a family of curves that we can adopt...

then we apply (1,4) into it to see what our anchoring constant turns out to be, right?

Answer 16

yea correct

Answer 17

then "suit up" and find our constant :)

Answer 18

i got 6

Answer 19

4 = 3 +2 -7 +C

4 = 5-7 + C

4 = -2 + C

6 = C

F(x) = 3x^4 +2x^3 -7x +6

yay!!!

Answer 20

thanks so much. Can you take a look at the other antiderivative I posted. I am getting confused, he took like 2 antiderivatives?

Answer 21

Didja notice me new "title"..... funny, i never was a sandwich before :)

Answer 22

hahaahahaah

Answer 23

ill check em out...

Answer 24

its 2 below the this question