Question

How do I get the x and y intercept of 4-2^x+3?

Answer 1

The x intercept occurs when y = 0. And the y intercept occurs when x = 0. Since your equation is y = 4 - 2^x +3, simply plug in 0 for one of the two variables, and solve for the other.

Answer 2

How would I go on solving for x? That's what confuses me. I understand how to get the y.

Answer 3

0=4-2^x
2^x=4
x = 2 (since 2² = 4)

Answer 4

Is the equation:

\[y=4-2^x + 3\] or \[y=4-2^{x + 3}\]

Answer 5

oops sorry forgot about the 3

Answer 6

i need to sleep lol ... sorry

Answer 7

To get a variable out of the exponent one would typically use a log function. Unless you can do it easily by inspection.

Answer 8

The second one Polpax. Thanks for trying kiwi :)

Answer 9

Ok, so

\[y=0 \rightarrow 2^{x+3} = 4\]
Since we know
\[4 = 2^2 \rightarrow 2^{x+3} = 2^{2} \rightarrow x+3 = 2 \rightarrow x = ?\]

Answer 10

Thanks Polpak :)