Question

in point O with radius 6, m arc AB=60.find the area of the shaded sector.

Answer 1

\[{(n+1)^{2}(n+3)!}/(n+1)!(3^{2n+2}) * {n!3^{2n}}/(n^2(n+2)!)\]

Answer 2

The area is in proportion to the degree of the arc. So,\[\frac{60^o}{360^o}=\frac{l}{2\pi r}\]where l is your arc length here, r the radius. Then\[l=\frac{2 \pi r}{6}=2 \pi\] since your radius is 6.