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∫ x^3 e^-x dx integrate using the appropriate technique of integration.
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Use some integration by parts on that guy; let u = x^3 and v'=e^-x.
ok.. u=x^3 v=e^-x u'=3x^2 v'= ...????
No, dv/dx = e^-x. You can't set v without first setting v', when doing integration by parts.
You're going to end up doing that type of integration 2 or 3 times if I'm not mistaken; unless you're familiar with tabular integration.
∫ U dV = UV -∫ V dU ???? thats right..???
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Yes, once you get that second ∫v du you're going to get another ugly one, so do integration parts on that one too.
ohhhh... confius..
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