how do i put ln[ sectheta + tantheta] in terms of x

Question

anonymous · Answer

a. There's no "x" in this expression.
b. In order to put it in terms of a variable; it has to be in an equation form.

anonymous · Answer

the ogrinal equation from solving it was intergal of dx/1-x^2 if that helps

anonymous · Answer

true, isn't there a given x np?

anonymous · Answer

HaHaHA  (breaking down due to extreme lough)

anonymous · Answer

lol, what's so funny angoo?

anonymous · Answer

I don't know

anonymous · Answer

Ahhh, so you used a trig substitution. Now, go back to whatever value you used for x to solve the integral (in terms of theta), solve for sec(theta) and tan(theta) by drawing out the triangles, and put those values - in terms of x - in your final expression.

anonymous · Answer

>_> seriously AG

anonymous · Answer

just wrote that to make you smile

anonymous · Answer

did you understand what Quantum said np65? ^_^

anonymous · Answer

and it made me smile :)

anonymous · Answer

so i have the triangle would that put me at 1-x^2+x then?

anonymous · Answer

for the answer

anonymous · Answer

what was your value of x when you integrated?

anonymous · Answer

What trig substitution for x did you use to solve the integral?

anonymous · Answer

i set x=sin

anonymous · Answer

how did you set x = sin?

anonymous · Answer

alright i have the intergal of dx1-x^2 i set u =sintheta and du = costheta dtheta

i then subed in u and du

anonymous · Answer

following that i got dtheta/costheta

anonymous · Answer

oh I got it!$$x = \sin \theta$$

and you know that sin x = opposite/hyp

your opposite in this case = x
hyp = 1

draw the triangle and you'll be able to continue from here

^_^

anonymous · Answer

hence :$$\sec \theta= 1/\cos \theta$$
$$\tan \theta = \sin \theta/ \cos \theta$$

you have sin (theta), now find cos (theta) 

:) is it clear now?

anonymous · Answer

so then the other side would be 1-x^2 or use the p-thag therom to get the last side making it the sqrroot(-x^2+1)

anonymous · Answer

use the pyth.theorem :) that's it. you just don't have x, find it by applying the theorem , then find cos (theta)

anonymous · Answer

so the last side will be :

$$\sqrt{1- x^2}$$ ^_^

anonymous · Answer

awesome got it now

anonymous · Answer

thanks

anonymous · Answer

np :)