Question

(-2x^2)^-3/9x^-2

Answer 1

since you have negatice powers you can switch the top with the bottom and the bottom with the top to get the powers positive and you'll get something like this:\[= x^2/(-2x^2)^3(9)\]\[=x^2/-72x^5 = -1/72x^3\]

^_^

Answer 2

(-2x^2)^-3/9x^-2 = [(-2)^(-3) x^(-6)]/[9x^(-2)] = 1/[(-2)^3 * 9 * x^4] = -1/[72x^4] = (-1/72)x^(-4)

Answer 3

sstarica, (x^2)^3 is x^6

Answer 4

oh yeah, I'm sorry :) thank you sklee ^_^

Answer 5

you're welcome

Answer 6

:)