A 10 ohm resistor is connected across a 120V rms sinusoidal 60Hz line. what value is the closest to the average current flowing in the resistor between t=0 and t=.0042 sec? (Hint V=120√(2)sin120pi t)

Question

A 10 ohm resistor is connected across a 120V rms sinusoidal 60Hz line. what value is the closest to the average current flowing in the resistor between  t=0 and t=.0042 sec?                           (Hint V=120√(2)sin120pi t)

radar · Answer

Convert the 120 RMS to Average, divide by the 10 Ohm resistor.

anonymous · Answer

Thank you!!!!!

anonymous · Answer

radar can you help me ?

radar · Answer

There is a conversion factor, but I do it the hard way first I convert RMS to Peakk, then peak to Average 120 x 1.414 = 170 peak, then multiply 170 x .6366 = 108 avg volts.  The rest is history.

radar · Answer

Oh Oh  looking up at your original you are asking for the instantaneous avg current at two specific times.  I was just computing the overall average current for 1/2 cycle.  You are making the problem difficult or at least someone Is.

Note the multiplying of 120 by the sqrt of 2  This is the conversion to pk voltage.

radar · Answer

I am going to have to do some review!  I will get back to you.

anonymous · Answer

Hey Radar,Thank you for your replays.I get it after your first replay.Some nick name Emy mistakenly did ask you for help on my page.

radar · Answer

O.K.  alma1969.  But I am stumped for the time being.