Question

relative extrema of x^3(x+1)^2

Answer 1

first differentiate it to get f'. then equate f'=0 to get the critical points.
differentiate again to get f". check which point that will yield f">0. then the x is the relative minima.

Answer 2

for relative extrema, check which x u got yield f"<0

Answer 3

product rule right?

Answer 4

yes.

Answer 5

for the (x+2)^2 part, do i do (x+1)(x+1) and derive the product of that?

Answer 6

no. use this:
if f(x)= (g(x))^n then f'(x) = n*g'(x)*(g(x))^(n-1)

Answer 7

3x(x+1)^2 + (2x+2)(x^3)?

Answer 8

Yes except you forgot the square on your first x

Answer 9

3x^2*(x+1)^2 + (2x+2)(x^3). u forgot the square at front.

Answer 10

how about 2x+3x^(2/3)?

Answer 11

i end up getting 2x^(-1/3) +2

Answer 12

thats correct

Answer 13

from there i get 2/cube root x +2?

Answer 14

yes.

Answer 15

how do you do absolute value problems?