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Mathematics 8 Online
OpenStudy (anonymous):

simplify sinx + cosx * cotx

OpenStudy (anonymous):

\[\sin x + \cos x \cot x = \sin x + \cos x \frac{\cos x}{\sin x}=\frac{\sin ^2x+\cos^2 x}{\sin x}\]\[=\frac{1}{\sin x }=\csc x\]

myininaya (myininaya):

i wanted to say that lol

OpenStudy (anonymous):

sorry

myininaya (myininaya):

lol you were here first

myininaya (myininaya):

tutoring is a cut throat world

OpenStudy (anonymous):

do dmromero's problem

OpenStudy (anonymous):

i don't know how you got from step 2 to step 3

OpenStudy (anonymous):

help!

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

sorry, left the page

OpenStudy (anonymous):

You get from step 2 to 3 by cross multiplication.

OpenStudy (anonymous):

nevermind i got it ' multiply by sinx/sinx is possible

OpenStudy (anonymous):

\[\sin x + \cos x \frac{\cos x }{\sin x}=\frac{\sin x }{\sin x }\sin x + \cos x \frac{\cos x}{\sin x}\]\[=\frac{\sin^2 x + \cos^2 x}{\sin x }\]because of the common denominator.

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

you're welcome. fan me! ;)

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