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Change the Cartesian Integral into an equivalent polar integral then evaluate: (int(int(dydx)) from -1 to 1 and 0 to sqrt(1-x^2)
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nvm got it...
How'd you do it? If I may
YOu have to graph the boundaries then find the new boundaries: 0 to pi/2 and 0 to 1. Then you use the equation int(int(rdrdtheta) which = pi/2
limits for r are 0 to 1, theta 0 to pi
I got 0 to pi /2 because its y...
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\[\int\limits_{}{}\int\limits_{}{}dxdy=\int\limits_{}{}\int\limits_{}{}|\frac{\partial J(x,y)}{\partial (r, \theta)}|dr d \theta=\int\limits_{}{}\int\limits_{}{}r dr d \theta\]
Integrate out r from 0 to 1, then theta from 0 to pi.
You get \[\frac{\pi}{2}\]
ohh i see that thanks
welcome. i stopped on your question and went for a shower - thought someone was taking it.
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