Question

how do i solve 3/ -4k^2- 5sqrt k^4?

Answer 1

is the equation:

(3/-4k^2) - 5 sqrt(k^4) ?

Answer 2

no its 3 over the entire -4k^2- 5sqrt k^4.

Answer 3

3/ (4k^2 -5 sqrt(k^4)) then?

Answer 4

with the (-)

Answer 5

yes

Answer 6

lets work on that "sqrt(k^4)" and see if we cant "undo" it..ok?

what do you know of square roots and exponents?

Answer 7

they r opposites of each other. you can use one to undo the other.

Answer 8

good... how can we re-write sqrt(k^4) so that we can "undo" it?

sqrt(k^2 k^2) is a start; and everything with a "^2" can be taken out right?

So,

kk can come out, which = k^2

do you agree?

Answer 9

yes

Answer 10

Then lets see how this helps us with the rest of the denominator:

4k^2 -5k^2

what can we do with this?

Answer 11

i keep forgetting the (-).

-4k^2 -5k^2

Answer 12

its cool. we can take out k^2 rite?

Answer 13

yes, you are right...

k^2(-4-5) = -9k^2 right?

Answer 14

yea

Answer 15

now lets look how this helps us with the rest of it:

3/(-9k^2) do you see anything else we can do to this?

Answer 16

3
------
-9 k^2

Answer 17

-1
-----
3k^s ?

Answer 18

yes, exactly :) even tho the ^s is a typo.... I will let it slide :)

Answer 19

thank you so much!

Answer 20

youre welcome...