Question

off subject..but can yall help me figure this problem out PLEASE?!

24v^2 + 5v - 36 i have to do the reverse FOIL method

Answer 1

(8x - 9)(3x + 4)

Answer 2

Recognize that\[24v^2+5v-36=8v \times3v+8v \times4-9\times3v-9\times4\]

Answer 3

Take out the common factors,\[8v(3v+4)-9(3v+4)\]

Answer 4

i.e.\[(3v+4)(8v-9)\]

Answer 5

It's the reverse way of going about FOIL.

Answer 6

thank you i find these hard to figure out

Answer 7

Have you been taught the quadratic formula yet?

Answer 8

If not, don't worry, but I was just asking because you can use it to give you a clue as to what factors to use...

Answer 9

umm i dont know...

Answer 10

It's okay. For now, you just have to find the right combination of factors by trial and error.

Answer 11

okay....math is very hard

Answer 12

Yeah, you just have to practice.

Answer 13

what about this one 16x^2 +32xy +15y^2

Answer 14

\[16x^2+32xy+15y^2=4x \times 4x -4x \times 5y-3y \times 4x +2y \times 5y\]

Answer 15

\[=4x(4x-5y)-3y(4x-5y)\]\[=(4x-3y)(4x-5y)\]

Answer 16

Wait up, I stuffed one of the signs...long day

Answer 17

ok

Answer 18

should be

Answer 19

thank you

Answer 20

\[16x^2+32xy+15y^2=4x \times 4x +4x \times 5y+3y \times 4x + 3y \times 5y\]

Answer 21

\[=4x(4x+5y)+3y(4x+5y)\]\[=(4x+3y)(4x+5y)\]

Answer 22

Does your teacher expect you to eyeball solutions to these?

Answer 23

no we have to show work,

Answer 24

that was the last one on that lesson. Now its - Diffrence of Squares and Perfect Square trinomials

Answer 25

How many questions are there?

Answer 26

30

Answer 27

I mightn't be around for much longer. Do you want me to see if there's someone else that can help?

Answer 28

yes please

Answer 29

I'll try to help out, yet I won't be here for long though

Answer 30

oh ok thank you

Answer 31

16a^2- 25b^2

Answer 32

the book says the answer is " no" how is that

Answer 33

you can write it like this too :\[4^2a^2 -5^2b^2\]
all you have to do is simplify it into 2 brackets, give it a try :)

Answer 34

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Answer 35

so you find the square of the 16 and 25

Answer 36

No...

Answer 37

why not?

Answer 38

wait, isn't the question = factor?

Answer 39

You have something in the form,\[a^2-b^2\]These things are called 'difference of two squares' and it factors as\[a^2-b^2=(a+b)(a-b)\]

Answer 40

factor right?

Answer 41

it says for each binomial is the binomial a diffrence of squares

Answer 42

\[16a^2-25b^2=(4a)^2-(5b)^2=(4a-5b)(4a+5b)\]

Answer 43

lol, that's what I've meant loki!

Answer 44

I wanted him to give it a try :)

Answer 45

oops..sorry :(

Answer 46

it's alright :)

Answer 47

dina did you understand the general concept of how to solve the problem?

Answer 48

so its a NO because one is plus and one is minus?!

Answer 49

Your answer is YES

Answer 50

If it factors like it factored above, it is a difference of two squares, so your answer would be YES.

Answer 51

uhhh ok im getting confused lol

Answer 52

try the general formula loki showed you which is :

(a-b)(a+b) use the FOIL method to check whether it's equal to :
\[a^2-b^2\]
as long as you understand the general concept of this question, you'll be able to proceed on your own , okay? :)

Answer 53

Exactly

Answer 54

clear dina? ^_^

Answer 55

i think so

Answer 56

all of the questions are the same, all you have to do is write them in the form of \[a^2-b^2\]

and you\'ll be fine ^_^

Answer 57

then apply the rule which is (a-b)(a+b) and use the FOIL to check your answer, and you'll ace it ! :)

Answer 58

thanks guys!

Answer 59

np ^_^, did you undestand?

Answer 60

So you get it then?

Answer 61

i think for now at least

Answer 62

good!

Answer 63

awesome :) , just practice one to check your understanding

Answer 64

and you'll get it

Answer 65

loki, lemmy get you up top real quick pleasee

Answer 66

ok...16a^2 - 12b^3

Answer 67

(4 + a)

Answer 68

for the first part?

Answer 69

you can take 4 as a common factor , so you'll have:\[4(4a^2-3b^2) = 4(2a -b)(2a+3b)\]

correct me if I'm wrong

Answer 70

That is not correct

Answer 71

First of all he has b^3 and second of all you can't write 3 as a perfect square.
All you can do is take out the 4

Answer 72

lol, I'm rushing can you take the lead blexting>?

Answer 73

Sure...

Answer 74

oh right! i forgot abt b^3

Answer 75

sorry

Answer 76

dina are just trying to factor?

Answer 77

the answers either yes or no

Answer 78

the answers either yes or no

Answer 79

to "is it a perfect square" is that the question?

Answer 80

This last one was NOT a perfect square.

Answer 81

yes

Answer 82

yes

Answer 83

OK.. what is the next one

Answer 84

thats it for now my daughter just wooke up thanks for all the help! i appreciate it

Answer 85

OK