Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

LOKI!!!!!!

OpenStudy (anonymous):

\[\int\limits_{}^{} (\ln(x))^{?}\]

OpenStudy (anonymous):

= x ln(x) - x + C.

OpenStudy (anonymous):

my bad: \[\int\limits_{}^{} (\ln(x))^{3}\]

OpenStudy (anonymous):

the original equation is (if you can help me with that instead): \[\int\limits_{}^{} 1\div x(\ln(x))^{3} \]

OpenStudy (anonymous):

1/[(x(ln(x))^3]?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

use u=lnx du=dx/x then you get ∫du/u^3

OpenStudy (anonymous):

nope, you get du/x^2u^3

OpenStudy (anonymous):

o...nvrmnd i was loking at dx, not du

OpenStudy (anonymous):

yup that works

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

Sorry arman, I didn't see it :(

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!