Three-fourths of seven less than a number is forty-two. Find the number.
my ans is -147/4
(3/4)(x-7) = 42. Gogogo
\[\frac{3(x-7)}{4} = 42 \rightarrow \frac{4(42)}{3} = x-7 \rightarrow x=?\]
so the number is 49?
Close.. \[ x-7 = 56 \rightarrow x-7+7 = 56 +7 = x = ?\]
63?
Indeed.
ok i got another for you...i like your help
The real trick here is in setting up the problem initially. Being able to convert word problems into workable equations is a good talent to develop.
suzette did twice as many pushups as mark did. bonnie did five less pushups than mark did. if they did 71 pushups together how many did each do?
\[\text{Polpak I prefer } \implies\ \text{instead of} \rightarrow\] The latter looks to much like a limit.
Let S be the number of pushups Suzette did, and M be the number Mark did, and B is the number Bonnie did. Translate this sentence into an equation. "They did 71 pushups altogether."
Newton: \[ \lim_{n \rightarrow 0}\] Looks like a limit \[ \rightarrow \] doesn't. Not to me anyway. And in my homework I always use a single arrow instead of the double thing, so it feels more natural to me.
\[2s +m=5-m=71 ?\]
That's a bit of a leap. Try just using the variables I defined. If they all did 71 pushups then: \[ M + S + B = 71\]
Then we look at how M, S, and B are otherwise related.
"Bonnie did 5 less pushups then Mark" \[ \rightarrow B = M-5\]
"Suzzette did twice as many pushups as mark" \[ \rightarrow ?\]
2(m)=s
Right. Now, using what we know about S and B, we can go back to our original equation and find how many mark did. \[ M+S+B=71\] Using the fact that S=2M \[ \rightarrow M + 2M + B = 71\] Using the fact that B=M-5 \[ \rightarrow ?\]
im lost
I plugged in 2M for S in the M + S + B = 71 equation. Now do the same for B.
m-5=b
Yes, that's the equation for what B _is_. Now use that in the equation M + S + B = 71
im so confused
B = M - 5. Would you agree then that M + S + B = M + S + (M-5) ?
ok
And since S = 2M Would you agree that M + S + (M-5) = M + 2M + M - 5 ?
i think
\[ S = 2M \] \[\rightarrow M + S = M + 2M \] \[ B = M-5\] \[ \rightarrow M + S + B = M + S + (M-5) \] \[ = (M + S) + (M-5) = M + 2M + M-5\]
Does that make sense?
not at all
S = 2M S + 5 = 2M + 5 right?
If S = 2M then S + SOMETHING = 2M + SOMETHING
That is what equals means
I don't understand what you're not understanding. Which part is confusing?
im a retard when it comes to math...i dnt even know where to begin to solve ur problem
Do you understand what S = 2M means? It means that anywhere you have an S, you can replace it with a 2M and it will mean the same thing.
ok i understand that
So if we have an equation M + S + B = 71, we can replace the S with 2M right?
yea
So rewrite the equation by replacing the S. Also replace the B since we know that B = M-5.
M+2(M)=71?
Not quite. M + 2M = 71 is the same as saying M + S is 71. But we know that's not true because M + S + B is 71 and B is not 0. M + 2M + B = 71 is true. But since we know B = M-5 we can replace B in this equation and we get?
M+2M+M-5
Right. Now, since we said that M + S + B = 71 and we said that M + S + B = M + 2M + M - 5 Then we know that M + 2M + M - 5 = 71 So solve for M.
32m 16s 23b
?
thats not right
\[ M + 2M + M -5 = 71\] \[ \rightarrow 4M -5 = 71 \] \[ \rightarrow 4M = 76 \] \[ \rightarrow M = 76/4 \] \[ \rightarrow M = 19 \]
38 19 14
S = 2M = 2(19) = 38 B = M-5 = 19-5 = 14
the sum of three numbers is -48. the first number is 12 more than the secong number, andthe third number is 20 less than twice the second number. find the three numbers.
Ok. This one you're gonna need to put more of the effort into. First pick variables for each of your 3 numbers (A, B, C?). Then take each sentance and see what it's telling you about your numbers. (Try to write the sentance as an equation)
The first sentance is: The sum of the three numbers is -48. So your equation is ?
a+b+c=-48
Perfect. Now the next sentence. The first number is 12 more than the second. Therefore?
A=12+B
And finally, The third number is 20 less than twice the second number.
C=20-2(b)
Not quite.
2B = twice the second number. twenty less than twice the second number = twenty less than 2B = 2B - 20 If 2B is 10, than 20 - 10 is not twenty less than 10.
20-2(b)=C
No.
C = 2B - 20
ok
?
So now put them all together. You have 1 equation with all 3 elements, and 2 other equations that give you replacement values for A and C. So replace them in and solve for B.
once again im lost
A + B + C = -48 A = 12 + B So.. ? + B + C = -48 Fill in the ?
36
... No A = 12 + B. So (A) + B + C = (12+B) + B + C right??
ya
If A + B + C = -48 and A = 12 + B and C = 2B - 20 the (A) + B + (C) = ?
Just replace the A and the C.
with what?
With what they equal.
i cant tell you what a equals without knowing b
............... You do know what A equals. A equals 12 + B. Period. It may also be represented in a different way, but you at least know that much.
So put 12 + B where there is an A. And put 2B-20 where there is a C.
12+b+2b-20
Right. And what does that equal again?
=-48
So what does B equal ?
Actually that's not quite right.
-8
you have 12 + B + 2B - 20 which equals (12+B) + (2B-20) which equals A + C. You forgot the B in the middle.
Rewrite the equation again. A + B + C = -48, A = B + 12, C = 2B-20 So...
idk man
im dying here
A + B + C = (12+B) + B + (2B-20) ^A + ^B + ^C Right?
yea
So if A + B + C = -48, what is B.
-36
\[12 + B + B + 2B - 20 = -48\] \[\rightarrow 4B - 20 + 12 -12 + 20 = -48 - 12 + 20 \] \[\rightarrow 4B = -60 + 20\] \[\rightarrow 4B = -40\] \[\rightarrow B = -10\] \[\rightarrow A = 12 + B = 12 + -10 = 2 \] \[\rightarrow C = 2B-20 = -20 -20 = -40 \]
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