find the area of r that is bounded by the graph of y=x^2-1 and the graph of x=y^2

Question

anonymous · Answer

is this for single or multi-variable calculus?

amistre64 · Answer

do I dare?  :)

nowhereman · Answer

It's single variable calculus.

amistre64 · Answer

this would be easier if we do it with respect to the y axis right?

anonymous · Answer

I don't think so.

amistre64 · Answer

I get pretty little intervals on the up and down tho ....

anonymous · Answer

Err. Oh. Yes, doing it with respect to y is best. I misread the equation.

anonymous · Answer

if this is for multi-variable, I would integrate w.r.t. x first, if it is for single- then use the little formula for area between two curves wr.t .y

anonymous · Answer

It's single variable.

anonymous · Answer

@ polpak, Is this your question?

amistre64 · Answer

is this equivalent to:

y=x^2

y = sqrt(x-1)

??  I think I did it right, but aint sure...

amistre64 · Answer

y=sqrt(x+1)  wrote down wrong.... im good

anonymous · Answer

$$f_1(y) = \sqrt{1+y}$$
$$f_2(y) = y^2$$

anonymous · Answer

agreed

amistre64 · Answer

I see the points on the paper, I just cant get to them :)

amistre64 · Answer

x^4 -2x^3 -x +1 = 0 .... is this even right yet?

amistre64 · Answer

can we modify this with trig?  use polar coordinates?  just wondering..

If we add the functions together, can we get the area that way?

amistre64 · Answer

not adding i guess... maybe subtracting :)