The directions say simplify. I didn't know how to type this so over means like a fraction and the brackets should cover both upper and lower numbers.

{-3(a^2b^-1)^3}^-2
over
{7(a^-5b^6)^-1}

Question

The directions say simplify. I didn't know how to type this so over means like a fraction and the brackets should cover both upper and lower numbers.

{-3(a^2b^-1)^3}^-2
over
{7(a^-5b^6)^-1}

anonymous · Answer

Is this it?
$$\frac{[-3(a^2b^{-1})^3]^{-2}}{7(a^{-5}b^6)^{-1}}$$

anonymous · Answer

No the brackets are over the bottom too so that the whole fraction is to the ^-2

anonymous · Answer

Ok so

$$[\frac{-3(a^2b^{-1})^{3}}{7(a^{-5}b^6)^{-1}}]^{-2}$$

anonymous · Answer

Yes that's it

anonymous · Answer

So start with what's inside the brackets. Specifically work on the numerator. What do you have when you evaluate
$$(a^2b^{-1})^3 = ?$$

anonymous · Answer

(a^6b^-3)

anonymous · Answer

Correct. Now the denominator.

anonymous · Answer

(a^-5b^-6

anonymous · Answer

Not quite.

anonymous · Answer

(a^-5b^6)

anonymous · Answer

Sorry I have to leave  I'll have to come back to this later

anonymous · Answer

$$(a^{-5}b^6)^{-1} = a^{\text{-5 * -1}}b^{\text{6*-1}}$$