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OpenStudy (anonymous):
alright, let's factor :
\[(3x + 5)(x + 1) = 0\]
use the FOIL method to check your answer ^_^
OpenStudy (anonymous):
how do you figure them out so easy
OpenStudy (amistre64):
skill and class :)
OpenStudy (anonymous):
exactly lol ^_^ , practice makes perfect :)
Believe me, I was so bad at these lol
OpenStudy (anonymous):
class hasnt helped me lol
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OpenStudy (anonymous):
class won't help, it just introduces the concept, only you can help yourself :)
OpenStudy (amistre64):
it helps when 3 and 5 make 8 right in front of you tho, but it takes practice to notice it ...
OpenStudy (amistre64):
i use the first and last numbers, and the signs of the middle and last numbers to figure alot of it out....
OpenStudy (anonymous):
i have the test tomarrow so we'l see
OpenStudy (amistre64):
there are some underlying concepts to be aware of that help.... like how the equation is constructed to begine with and that way you can more easily tear it apart
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OpenStudy (anonymous):
so on this next one- 5w^2 + 13w - 6
OpenStudy (anonymous):
you're going to do great ^_^
OpenStudy (amistre64):
5(6) = 30... the last signis negative so the signs are different and its subtraction.... the middle number is positive so the largest factor is the positive...
OpenStudy (amistre64):
(w+/5)(w-/5) is my setup...
OpenStudy (amistre64):
1,30; 2,15, 3,5 15-3=13 use it
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OpenStudy (amistre64):
(w+15/5)(w-2/5) simplify and shift
OpenStudy (amistre64):
(w+3)(5w-2)
OpenStudy (anonymous):
ok so what the first and last multipy out to the middle needs to add up to that number
OpenStudy (amistre64):
want me to go slower :)
OpenStudy (anonymous):
yes please
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OpenStudy (amistre64):
the first number is used to "calibrate" the rest. does that make sense?
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
ok... the last number is used with the first number to find a "pool" of options for our middle number... does that make sense?
OpenStudy (anonymous):
yea
OpenStudy (amistre64):
5(6) = 30...what are our options...all of them...
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OpenStudy (anonymous):
the factors of 30
OpenStudy (amistre64):
yes, what are they so we can see them :)
OpenStudy (amistre64):
start with the obvious..1,30; and move on
OpenStudy (anonymous):
15*2 6*5 30* 1
OpenStudy (amistre64):
thats good, lets keep those available while we "setup" our answer
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OpenStudy (amistre64):
the last number is gotten by multiplication right? so the sign of that number tells us alot of what we need to use
OpenStudy (amistre64):
if the sign is (-) what are our options?
OpenStudy (anonymous):
15-2 ?
OpenStudy (amistre64):
well get to that... but for now, focus on the sign only and not the value of the number...
our set up is this:
( w ) (w ) we need some signs....
OpenStudy (anonymous):
one of each
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OpenStudy (anonymous):
plus and minus
OpenStudy (amistre64):
good job.... now look at the middle number and that tells you which number is bigger... does that make sense?
OpenStudy (amistre64):
whats the middle sign? + or -?
OpenStudy (anonymous):
-
OpenStudy (amistre64):
that middle number is +13 right?
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OpenStudy (anonymous):
yea
OpenStudy (amistre64):
then we want our "bigger" numbe that we use to be (+)
(w + B )(w - L ) got it?
OpenStudy (amistre64):
now which factor do we see that will subtract to get 13?
OpenStudy (anonymous):
15 2
OpenStudy (amistre64):
good
(w +15 )(w -2 )
couple more loose ends to wrap up
we used that "5" from the front to begin with and so we need to divide it out in this step like this:
(w +15/5 )(w -2/5 ) makes sense?
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OpenStudy (anonymous):
yes
OpenStudy (amistre64):
simplify those fractions and if they still look like a fraction... move the bottom in front of its x partner like this:
(w +3 )(w -2/5 ) cant reduce anymore so move the denoms if there is any:
(w +3 )(5w -2) and were done
OpenStudy (anonymous):
thank you so much our teacher goes to fast
OpenStudy (amistre64):
lets do another one so I can see you do it :)
OpenStudy (anonymous):
ok....2x^2-2x-40
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OpenStudy (amistre64):
if it cant be done like this...use the quadratic formula :)
OpenStudy (amistre64):
first step is what?
OpenStudy (anonymous):
find the factors of 40?
OpenStudy (amistre64):
close, first time last for a pool
OpenStudy (amistre64):
2(40)
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OpenStudy (amistre64):
use that first now so we can divide it later... whats our pool?
OpenStudy (anonymous):
oh ya...let me write this down
OpenStudy (amistre64):
no writing...must do it the hard way :)
OpenStudy (anonymous):
ok...80
OpenStudy (amistre64):
write it down.... :)
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OpenStudy (anonymous):
i did lol
OpenStudy (amistre64):
what are our "factors" of 80 to choose from?
OpenStudy (anonymous):
2*40 8*10
OpenStudy (anonymous):
80 *1
OpenStudy (amistre64):
1,80; 2,40; 4, 10; 8, 5
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OpenStudy (amistre64):
8 and 10 lol forgot how to multiply
OpenStudy (amistre64):
1,80; 2,40; 4,20; 8,10; 16; 5
thats better
OpenStudy (amistre64):
lets start setup....
2x^2-2x-40
(x )(x ) we need signs...what are they?
OpenStudy (anonymous):
ok...both -
OpenStudy (amistre64):
both (-) meaning? that (-)(-)=(-)?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
one of each
OpenStudy (amistre64):
the last number sign tells us we need to multiply some signs to get it....
OpenStudy (amistre64):
good, and the middle tells us which is begger right?
OpenStudy (amistre64):
or bigger depending on your accent :)
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OpenStudy (anonymous):
yes
OpenStudy (amistre64):
(x- B )(x+L ) we good so far? you writin this down?
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
2x^2-2x-40
what numbers from our pool will give us 2?
OpenStudy (anonymous):
10 8
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OpenStudy (anonymous):
+10 -8
OpenStudy (amistre64):
good. lets fill them in
(x-10 )(x+8 ) now divide out the first number that "2" we used
(x-10/2)(x+8/2) now what?
OpenStudy (anonymous):
(x-5)(x+4)
OpenStudy (amistre64):
thats right.... but let me check our work a second....
OpenStudy (amistre64):
one little after thought that usually doesnt come up is this..... we could have factored out a "2" to begin with.
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OpenStudy (anonymous):
as the gcf
OpenStudy (amistre64):
yep.... so we actually need to put it back in like this:
2(x-5)(x+4) to make everything right again :)
OpenStudy (amistre64):
now this will work back into the original :) you tried to trick me didnt you :)
OpenStudy (anonymous):
haha ya
OpenStudy (anonymous):
thanks..you helped alot
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OpenStudy (amistre64):
youre welcome.... hope you do good :)
OpenStudy (anonymous):
il get on toarrow night and let you know if your here my class is at 8am
OpenStudy (amistre64):
8am eh... is that florida time?
OpenStudy (anonymous):
nm
OpenStudy (amistre64):
ahh.... your 2 or 3 hours behind me then
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OpenStudy (anonymous):
ya its 11
OpenStudy (amistre64):
:) library is closing here at my college.... so have fun :)