Question

HELP ME SIMPLiFY:

Answer 1

1.\[15a ^{-4}b ^{-6} \over 3a ^{7}b ^{-10}\]

Answer 2

steps please :)

Answer 3

alright, let's get the negative powers positive by switching their places and we'll get :\[= (15b^{10})/(3a^7a^4b^6)\]

so now we know that :
\[= (3)(5)b^{10}/3a^{11}b^6\]

let's cancel out the commons and simplify ^_^:
\[= 5b^4/a^{11}\]

get the idea now? :)

Answer 4

we subtract the powers :)

Answer 5

i am confused on the top part...you but 3a^7 a^4 .... how did you get two a's

Answer 6

lol, okay, we want to get the powers (+) instead of (-) so in order to do that, if we have a negative powe in the top we get it down to get it positive and vice versa ^_^

Answer 7

power*

Answer 8

so I got a^-4 down to make it a^4 :)

Answer 9

to make your life easier ^_^

Answer 10

ok so you brought that down
i get that

Answer 11

how did you get b ^10

Answer 12

yep, same thing goes with b too ^_^

Answer 13

oh since it was - you brought it up to be pos.

Answer 14

you want b^-10 positive, so you get it up to make it b^10 :) switch the places

Answer 15

exactly ^_^

Answer 16

ok

Answer 17

then we simplify and subtract, b^10 - b^6 = b^4 and the one with the greatest power takes the lead, which means the answer stays up :)

Answer 18

got the point? ^_^

Answer 19

yes thanks so much, i have two other problems i posted if you get a chance i would love your help!

Answer 20

np, I'll take a look ^_^