Question

3(y+7)/7y - (4y - 7)/6 = (7y+10)/3y - 2(7y-1)/21

Answer 1

solve for y

Answer 2

(3y+21/7y)-(4y-7/6)=(7y+10/3y)-(14y-2/21)
=> (3y+21/7y)-(7y+10/3y)=-((14y-2/21)+(4y-7/6))
am working on the rest of the computation

Answer 3

we will get i think -1596y²-567y+294=0 you need to do delta to find the solutions

am not sure about the computation though

Answer 4

ok so you should be able to simpliify it down to

42y^2 - 42y - 35 = 0

so factoring out a 7 would give you

6y^2 - 6y + 5 = 0

if you have learned imaginary roots:

0.5 +- i*(sqrt(21)/6)

Answer 5

Move the right side of the equation over to the left side leaving zero on the right side and after simplifing the left side you will have the following equation:
\[\frac{1}{42} \left(45-14 y-80 y^2\right)==0 \]
Solve
\[\left(45-14 y-80 y^2\right)==0 \]

Answer 6

I haven't learned about imaginary roots yet. :/ I'm just learning algebraic fractions...so I'm realy confused

Answer 7

\[y=\frac{1}{80} \left(-7\pm\sqrt{3649}\right)\]

Answer 8

now im rly lost....

Answer 9

After moving the right side to the left side, the left side should look like the following:
\[\frac{1}{6}(7-4y)+\frac{3}{7}y(7+y)-\left(-\frac{2}{21}(-1+7y)+\frac{1}{3}y(10+7y)\right)=0\]
Get rid of the fractions by multipling each fraction in front of it's term by 42, the smallest number divisible by all of the fraction denominators. Do the multiplications and collect like powers of x.