Question

how do i factor: 14x^2-47x+7=0

Answer 1

You don't.

Answer 2

oh.. ok well my original problem i needed to solve was -42x^2+141x=-21

and i thought i was on the right track... maybe not?

Answer 3

find delta and factor using the solutions

Answer 4

what is delta?

Answer 5

The only thing that will make 14x^2 is (7x )*(2x ). Now, the only factors that give the 7 is 7 and 1. With this knowledge you get (7x-1)*(2x-7)

Answer 6

Wrong; is it possible that taking out 3 was all you were meant to do? Because it can;t go any further.

Answer 7

hmm.. maybe but the example i followed came up with two terms which then i put to the zero factor property... but maybe this is as far as this one goes.

Answer 8

what about the p and q thing?

Answer 9

I put it through the answer check and it said that 14x^2-47x+7 was wrong

Answer 10

it said the methods to solving were either the quadratic formula or by completing the square.

Answer 11

\[\sqrt{47^2-4 \times 7 \times 14} \notin \mathbb{Z^+}\] therefore it won't factorise

Completing the square doesn't look too friendly on this one; just go with the formula

Answer 12

\[x = \frac{47 \pm \sqrt{1817}}{28}\]
...dunoo how that will go in your 'answer check'

Answer 13

haha yeah.. probably not that well.. but thanks for the help @INewton

Answer 14

just an update...

apparently 14x^2-47x+7=) factors into (7x+1)(2x-7)... which in turn would make the real number solutions: -1/7 and 7/2