Someone please help with surface area of pyramids and cones
are these answers correct? the first one i got 282.6m^2 the second one i got 175.84in^2
if you can cut the cone up its lengthand make into part of a circle, the surface area is easy to get :) maybe even easy if I think about it some
is the 10 inches the length up the side of the cone or the height?
length
its actually slant height
then that 10 inch length is the radius of a larger circle, find its circumference" 2pi10 20pi is its curcumference the small base circle is the length of the circumference that you want to find an area for 2pi4 = 8pi make sense?
kinda
\[s =\pi \times r ^{2}+\pi \times r \times l\] is the formula i need to use
length of an arc = theta(r) 8pi = theta(10) theta = 8pi/10 = 4pi/5 area of sector = theta r^2/2 (4pi/5)(10)(10)/2 200/5 = 40pi fpr the surface area of the cone, do we include that base in this or not?
40pi + 16pi = 56pi if I did it right :)
ok
would = 175.84in^2
175.92 is what I get... is that close enough?
175.84 if you use (3.14)
yea
how would i find the surface area of this one
if im doing it right, I get 85pi
would i use half the diameter?
if you dont have answers to check against, I would suggest gettting a second opinion :) but yes, radius is half the diameter
\[s =\pi \times 5^{2}+\pi \times 5 \times 12\]
i got 25pi + 60pi too :)
im glad the formula works :)
witch would = 266.9ft^2
would you please help me with three more
i could try.... getting kinda deer in the headlights feeling....must.....carry.........on. . . . . . . ok
find the surface area of the regular pyramid
#31 3cm is pointing to what?
3cm is height i believe
is it face height or pyramid height?
the formula for this on is S=B+1/2Pl
looks like pyramid hight
pyramid height would have a dotted line stricking down the middle of it..... i think its face height.
so do i
4cm^2 + 12 cm^2 = 16 cm^2 for #31
#32...all I see is a 7 and not much else for details...
thats all there is
is that all sides are 7? like an equalateral triangle?
yea
then I would do: 4 times (1/2)(49)sin(60) 84.87 m^2
if you have a side-angle-side, the area can be determined by: (side)(side)(sin(angle))/2 and there are 4 sides so I timesed it by 4 :)
(side)sin(a) = height, and the other side = base
ok
and for the last one its just like the first except with decimals..
(9.2)^2 + 4(9.2)(13)/2
84.64 + 239.2 = 323.84
okay thank you so much
youre welcome :)
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