Question

Reduction of order to solve second order differential equation.
y''(t+1)^2 - 4(t+1)y' + 6y = 0
Given y_1 = (t+1)^2

Answer 1

\[(t+1)^{2}y'' -4(t+1)y' + 6y = 0, y_{1}=(t+1)^{2}\]

Answer 2

This is Calc II or a Diff Eq class?