Question

Can someone tell me if this is right??
finding the slant height..
i got 473.96

Answer 1

what does it mean by slant height? the edge or the face?

Answer 2

idk.. it just says find the slant height of the regular pyramid

Answer 3

i googled it and it says slant height is the distance up the face.

that distance is equal to sqrt(15^2 + 6^2)

sqrt(225 + 36) = sqrt(261) right?

Answer 4

16.155 is what I get.....

Answer 5

okay.. i got 17.2

Answer 6

the slant height is just the hypotenuse of he right triangle that is formed by 15 and 12/2

Answer 7

I agree with Amiestre64

Answer 8

dont let the hero title fool ya..... im just an idiot in disguise :)

Answer 9

i got 2 hours to write up a paragraph on how well Johnson and Johnson company would be as a stock purchase...... procrastinating :)

Answer 10

Indeed.

\[15^2 + 6^2 = \text{Slant height}^2\]
\[ \rightarrow \text{Slant height} = \sqrt{15^2 + 6^2} = \sqrt{225+36} = \sqrt{261} \approx 16.1555\]

Answer 11

slant height for this one

Answer 12

Employ the same technique.

Answer 13

is that a 13 or an 18?

Answer 14

18

Answer 15

The 'legs' of the hypotenuse are 5 an 18

Answer 16

sqrt(5^2 + 13^2) then

sqrt(25 + 196)

Answer 17

er.... 169 :)

Answer 18

........ugh, maybe I do need to write that paragraph lol

Answer 19

18^2 not 13^2

Answer 20

8 and 1 are your legs there

Answer 21

where did the one come from

Answer 22

since the height of thing comes down to the middle of a side, the length you use for the bottom leg is just half of a side....2/2 = 1

Answer 23

oh

Answer 24

so for this one slant height is 18.68

Answer 25

this one slant height = 8.06

Answer 26

I get 8.246 for that last one.

Answer 27

Oh wait no. You're right.

Answer 28

8.06

Answer 29

it would be ft ^2 right

Answer 30

No. You have
\[\sqrt{ft^2 + ft^2} \]
So it will be in ft.

Answer 31

ok