How do i find the zeros and the multiplicity of 3(x+4)(x-7)^(2)
If you have your equation in fully factored form (you do) then each variable factor represents a 0 where the power of the factor is the multiplicity. So in this example what are your variable factors?
4 and -7
Not quite. Notice that (x+4) = 0 when x = -4. And (x-7) = 0 when x = 7
What class are you taking?
so its what ever make the eqations 0
Yes.
ok thank you how about the multiplicity
The multiplicity would be any exponent on the factor. Recall that if a factor has no exponent it's assumed to be raised to the first power. So would have a multiplicity of 1, while a factor squared would be multiplicity 2, etc.
ok thank you
The zeroes are -4 and 7. The multiplicity of -4 is 1. The multiplicity of 7 is 2.
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