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Find the derivative of the function. g(t)= 7/ ln(t)
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looks simple enough :)
7 Dt(1/ln(t))
use quotient rule: (f/g)' = f'g - g'f / g^2
- 7 ------------ t ln^2(t)
i hope that looks beter on your screen :)
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I tried this answer but it is incorrect. can u explain how u got this answer?
7/ln(x) f' = (bt'-b't)/b^2 b = ln(x), b'=1/x , t=7, t'=0 ln(x)(0) - (7)1/x / ln^2(x) -7/x ln^2(x) might be able to simplify it more
okay ill have to go ask for some more help b/c this is not a correct answer and i dont know y it is nt accepting my answer
thnxs
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No that is the correct answer, make sure you check that you're entering the (ln(x))^2 part correctly
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