Question

ln2000=ln20+0.825t what is the answer and how do you get it?

Answer 1

put the natural logs on one side and then combine them using lnx/y=lnx-lny property and then base e both sides

Answer 2

ln 2000 - ln 20 = 0.825t

ln (2000/20) = 0.825 t
t = (ln(2000/20)) / 0.825

Answer 3

i mean no base e

Answer 4

lol

Answer 5

so it goes like this:
ln200/ln20=.825t
ln100=.825t
t=5.582?

Answer 6

no it goes like this first step subtract ln20 on both sides giving you: ln2000-ln20=.0825t

Answer 7

now we can write ln[(2000/20)]=.0825t

Answer 8

ln(100)=.0825t

Answer 9

to solve for t we just divide now by .0825giving us [ln(100)]/(.0825)=t

Answer 10

remember that property: ln(x/y)=lnx-lny?

Answer 11

but isnt that what i did? im confused...you said to ln2000-ln20 (subtract) but instead you divided?

Answer 12

so what would be the final answer?

Answer 13

thats how i would write my final answer. ln(x/y) does not equal lnx/lny

Answer 14

oh ok i see so final answer when put in calc would be??

Answer 15

> ln(100.0)/(.0825);
55.82024467
>