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OpenStudy (anonymous):
domain of this function would be x<=2 since log is not defined for negative values
OpenStudy (anonymous):
so it is (- infinity, 2]
OpenStudy (anonymous):
got it jsy? or u need more clarification? :):)
OpenStudy (anonymous):
sry *jay
OpenStudy (anonymous):
Are you there???? @jay
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OpenStudy (amistre64):
ln is not define for zero either....when does ln(x) = 0?
OpenStudy (anonymous):
log 0 = 1 am i right?
OpenStudy (anonymous):
if its so, then the answer is (-infinity, 2)
OpenStudy (amistre64):
no...sorry :) thats better..
think of it this way. the log points to an exponent:
log2(8) = 3
the exponent is "3" the base is to "2"
2^3 = 8
now tell me....
2^? = 0 ??
OpenStudy (amistre64):
log2(0) = ?
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OpenStudy (anonymous):
then my second option is correct? isn't it? and not the first one...
OpenStudy (amistre64):
(-inf,2) is correct :)
OpenStudy (anonymous):
hmm.... yay amistre:)
OpenStudy (anonymous):
i think jay is not here
OpenStudy (amistre64):
jay was just the catalyst.... math goes on without him lol
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OpenStudy (anonymous):
:)but i think this shud help him
OpenStudy (anonymous):
i definitely see that as an option thank u so much
OpenStudy (anonymous):
you 're welcome:) any more questions??
OpenStudy (anonymous):
\[2-x \ge0\]\[x \le 2\]
hence the domain is \[[-\infty, 2)\]