Question

hi i need help with rationals

Answer 1

\[4/x+1=3/x+2\]

Answer 2

Is that:

a) \(\frac{4}{x} +1 = \frac{3}{x} + 2\)
b)\(\frac{4}{x+1} = \frac{3}{x+2}\)
c) neither a nor b

Answer 3

b

Answer 4

Multiply both sides by (x+1)(x+2). Then solve in the usual way. You just need to stipulate that \(x\ne-1 \text{ and } x\ne -2\).

Answer 5

:( i stil not understand

Answer 6

\[\frac{4}{x+1}=\frac{3}{x+2}\]
\[(x+1)(x+2) *\frac{4}{x+1}=\frac{3}{x+2} * (x+1)(x+2)\]

Answer 7

then the answer should be 7x+9 over (x+1)(x+2) im i correct.?

Answer 8

No.. There should be no denominator when you're done You should simply have x = a number.

Answer 9

\[\frac{(x+1)(x+2)}{1}*\frac{4}{x+1} = \frac{3}{x+2}*\frac{(x+1)(x+2)}{1}\]
\[4(x+2) = 3(x+1)\]

Answer 10

oh gawsh.!

Answer 11

And continue from there.

Answer 12

ohkay i multiplied nd got 4x+8=3x+3

Answer 13

x=5 correct

Answer 14

I have x = -5

Answer 15

yes thank you sooo much.!