Question

How do solve 2^( x+1) =x^2-1algebraically.

Answer 1

Recognize that \(x^2 -1\) is a difference of squares. Then factor it and cancel an (x+1) (with the restriction that x does not equal -1.

Answer 2

No, you can't solve it algebraically (exactly)

Answer 3

but on the left hand side we have 2^(x + 1)

Answer 4

so x +1 cant be cancelled out