Question

8 over x squared -4 plus 6 over 3x-6
solving quadratic equations :(?

Answer 1

8 6
------- + -------- like this?
x^2 - 4 3x-6

Answer 2

yes!

Answer 3

Does that equal something?

Answer 4

but i dont know HOW to get the answer :/

Answer 5

which is 2x +12
------
x^2-4

Answer 6

\[\frac{8}{x^2-4}+\frac{6}{3x-6}\]
\[= \frac{8(3x-6) + 6(x^2-4)}{(3x-6)(x^2-4)}\]
\[= \frac{8(3x-6) + 6(x+2)(x-2)}{(3x-6)(x^2-4)}\]
\[= \frac{8(3x-6) + 2(x+2)3(x-2)}{(3x-6)(x^2-4)}\]
\[= \frac{8(3x-6) + 2(x+2)(3x-6)}{(3x-6)(x^2-4)}\]
\[= \frac{(3x-6)[8 + 2(x+2)]}{(3x-6)(x^2-4)}\]
\[= \frac{[8 + 2(x+2)]}{x^2-4}\text{ , } x \ne 2\]
\[= \frac{[8 + 2x+4)]}{x^2-4}\text{ , } x \ne 2\]
\[= \frac{2x+12}{x^2-4}\text{ , } x \ne 2\]

Answer 7

Actually x cannot be -2 either.