Question

Determine the limit.

Answer 1

\[\lim_{x \rightarrow \infty} {{2x^2 - 3} \over {4x^3 +5x}}\]

Answer 2

0

Answer 3

?

Answer 4

\[\lim_{x\rightarrow\infty}\frac{2x^2-3}{4x^3+5x}=\lim_{x\rightarrow\infty}\frac{2-3/x^2}{4x+5/x}=\lim_{x\rightarrow\infty}\frac{2}{4x}=0\]

Answer 5

why \[/x^2\] and \[/x\] ?

Answer 6

ahhh! I get it!

Answer 7

Thanks!