Question

Q:f={(0,5),(1,4),(2,7),(3,14)} and g(x)=3f(x+1)+7

a)evalute g(-1)
b) evalute g (1)
c) evalute g(3)

Answer 1

a)22
b)28
c)is notdefined

Answer 2

i noe but how did u solve it can u show me tht

Answer 3

sure

Answer 4

a) g(-1)=3f(-1+1)+7=3f(0)+7
from the definition of f we see that f(0)=5

so g(-1)=3f(0)+7=3(5)+7=22

Answer 5

g(x) = 3f(-1 + 1) + 7
g(x) = 3f(0) + 7 find f(0) from the Q:F (0,5)
g(x) = 3*5 + 7
g(x) = 15 + 7
g(x) = 22

g(x) = 3f(1 + 1) + 7
g(x) = 3f(2) + 7 find f(2) = (2,7)
g(x) = 3*7 + 7
g(x) = 21 + 7
g(x) = 28

g(x) = 3f(3 + 1) + 7
g(x) = 3f(4) + 7 find f(4) = not listed don't know what to do

Answer 6

f is explicitly defined as the given set of ordered pairs, therefore there is nothing to "do" in part (c) , it is simply not defined

Answer 7

thannks :)