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Mathematics 11 Online
OpenStudy (anonymous):

consider the following radicals..

OpenStudy (anonymous):

\[7\sqrt{8}+\sqrt{18}\]

OpenStudy (amistre64):

radicals are like variables in this case, in order to add them together they have to be "identical" can we reduce these radical expressions to have the same radical stuff?

OpenStudy (amistre64):

7*2sqrt(2) + 3sqrt(2) = 17sqrt(2)

OpenStudy (anonymous):

oh yeah, I kind of remember how these go.. but what is the next step once we square them?

OpenStudy (amistre64):

not squareing :) we need to get them to "look" the same: sqrt(8) = sqrt(4*2) = sqrt(4) * sqrt(2) = 2sqrt(2)

OpenStudy (amistre64):

sqrt(18) = sqrt(9*2) = sqrt(9) * sqrt(2) = 3sqrt(2)

OpenStudy (amistre64):

now we can combine these puppies since they are both "sqrt(2)"s

OpenStudy (amistre64):

7*2sqrt(2) + 3sqrt(2) = 14sqrt(2) + 3 sqrt(2) = 17sqrt(2)

OpenStudy (amistre64):

does that make sense?

OpenStudy (anonymous):

yeah I kind of understand where it's going. Does the *=x? ha.. i'm definitely a visual learner so that is helpful to write out. Thanks!

OpenStudy (amistre64):

\[\sqrt{ab} = \sqrt{a}* \sqrt{b}\]

OpenStudy (amistre64):

* means multiply :)

OpenStudy (anonymous):

gotchaa. :)

OpenStudy (amistre64):

\[\sqrt{8}=\sqrt{4*2}=\sqrt{4} * \sqrt{2} = 2\sqrt{2}\]

OpenStudy (anonymous):

would some of those cancel out then?

OpenStudy (amistre64):

nope, since the problem calls for addition, the only way to cancel anything out would be to subtract like amounts.

OpenStudy (anonymous):

wait. sorry I just realized you were giving an example. ha okk

OpenStudy (anonymous):

ok. So which side do we want to subtract from? Sorry, i don't know what the format of this answer should even look like really so i'm a little confused

OpenStudy (amistre64):

lets try this...... 7a + b = ? How would you add these together considering that they are not the same variables?

OpenStudy (amistre64):

we would have to redefine the variables so that they were the same.... right?

OpenStudy (anonymous):

yep!

OpenStudy (amistre64):

so, we redefine them like this: a = 2x b = 3x now: 7(2x) + 3x = ?

OpenStudy (anonymous):

okk

OpenStudy (amistre64):

14x + 3x = 17x... right? not trying to solve for x....just trying to add them together

OpenStudy (anonymous):

yeah. makes sense

OpenStudy (amistre64):

radicals act just like these variables...... we have to redefine them to "match" each other before we can add them up.

OpenStudy (amistre64):

\[7\sqrt{8} + \sqrt{18}\]\[7(2\sqrt{2}) + 3\sqrt{2} = ?\]

OpenStudy (amistre64):

now that they are the "same" variable...we can add them up\[17\sqrt{2}\]

OpenStudy (anonymous):

ohh cuz 2 * 7 is 14 and then we add the 3..and does it stay 2 since they are both squared 2?

OpenStudy (amistre64):

yep... and the so-called "variable" is the sqrt(2) part.

OpenStudy (anonymous):

okk thanks so much for walking through that! so the answer is \[17\sqrt{2}\]

OpenStudy (amistre64):

exactly :)

OpenStudy (anonymous):

:):)

OpenStudy (anonymous):

quick question..again.. to find the product for (5+3i)(5-3i) would this just be 10? I think the 3i's would cancel out?

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