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define the integral of (1+x^2)/(x) from 1 to 2; i found the antiderivative of ln(x)+(x^2/2) but cant seem to find the correct answer is this right?
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Looks like your answer is correct. So if you're having problems I'd check the evaluation.
Should be ln(2)+3/2
[2+ln(2)]-[1/2+ln(1)]. ln(1) is 0 so you are left with [(3/2)+ln(2)] after you subtract 1/2 from 2
Thanks that makes more sense
Not sure what was confusing you but you find the antiderivative and subtract your smaller boundry from your larger boundry.
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I was not sure if that was the correct antiderivative Wiley told me i was wrong but it was only my input into wiley, got to love it
Internet homework is so much fun.
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