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Mathematics 20 Online
OpenStudy (anonymous):

find the product for (5+3i)(5-3i)... I got 24-9a. Does anyone know if this is correct?

OpenStudy (anonymous):

Should be 25-9i. You use foil if you've ever been taught that.

OpenStudy (anonymous):

No i, my bad.

OpenStudy (anonymous):

yeah, that's what I used.. and since the 9i was squared i added a -1. must have calculated it our wrong. Thanks

OpenStudy (anonymous):

yeah, do the i's cancel out? So it would be 25-9?

OpenStudy (anonymous):

And actually should be adding. Let's start over lol.

OpenStudy (anonymous):

ha good call!

OpenStudy (anonymous):

25-9i^2. That is what you should get, which can be simplified.

OpenStudy (anonymous):

ok so I can add the 2 and the 25?

OpenStudy (anonymous):

Ok. So i represents an imaginary number, it's what you get when you take the square root of a negative number. And the ^ is raised to a power. So we have 25-9i^2. So if \[i=\sqrt{-1}\] then \[i^2=-1\] So we get 25-9(-1)

OpenStudy (anonymous):

someone help me

OpenStudy (anonymous):

ok so would that be the answer? or can I simplify from there? Since there aren't any i's do I need to add those all to get one number?

OpenStudy (anonymous):

Yes to more simplifying. 25-9(-1) is the same as 25+9=34

OpenStudy (anonymous):

oh so the answer should be just 34?

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

Thanksabunch

OpenStudy (anonymous):

No problem. :)

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