find the product for (5+3i)(5-3i)... I got 24-9a. Does anyone know if this is correct?
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OpenStudy (anonymous):
Should be 25-9i. You use foil if you've ever been taught that.
OpenStudy (anonymous):
No i, my bad.
OpenStudy (anonymous):
yeah, that's what I used.. and since the 9i was squared i added a -1. must have calculated it our wrong. Thanks
OpenStudy (anonymous):
yeah, do the i's cancel out? So it would be 25-9?
OpenStudy (anonymous):
And actually should be adding. Let's start over lol.
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OpenStudy (anonymous):
ha good call!
OpenStudy (anonymous):
25-9i^2. That is what you should get, which can be simplified.
OpenStudy (anonymous):
ok so I can add the 2 and the 25?
OpenStudy (anonymous):
Ok. So i represents an imaginary number, it's what you get when you take the square root of a negative number. And the ^ is raised to a power. So we have 25-9i^2. So if \[i=\sqrt{-1}\] then \[i^2=-1\] So we get 25-9(-1)
OpenStudy (anonymous):
someone help me
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OpenStudy (anonymous):
ok so would that be the answer? or can I simplify from there? Since there aren't any i's do I need to add those all to get one number?
OpenStudy (anonymous):
Yes to more simplifying. 25-9(-1) is the same as 25+9=34
OpenStudy (anonymous):
oh so the answer should be just 34?
OpenStudy (anonymous):
Yep.
OpenStudy (anonymous):
Thanksabunch
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