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OpenStudy (anonymous):
find dy/dx by implicit differentiation: 1/(xy)^-2=x-y
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OpenStudy (anonymous):
Take the derivative as normal. So dy/dx is derivative of y with respect to x. When there is a y in the equation, we treat it similarly. So the derivative of y is dy/dx in this case. Once the derivative is found, solve for dy/dx.
OpenStudy (anonymous):
I'm still confused how would you take that derivative as normal?
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