Question

find dy/dx by implicit differentiation:
1/(xy)^-2=x-y

Answer 1

Take the derivative as normal. So dy/dx is derivative of y with respect to x. When there is a y in the equation, we treat it similarly. So the derivative of y is dy/dx in this case. Once the derivative is found, solve for dy/dx.

Answer 2

I'm still confused how would you take that derivative as normal?