how do u raise a fraction to a power
\[({a \over b})^{n} = {a^n \over b^n}\]
any chance u could put a fractin in im really confused with this sort of maths thanks
it says, if you want to raise any fration a/b (a symbolizing _any_ numerator and b symbolizing _any_ denominator) to the n-th power (n can be _any_ number - or even other expression), you get a fraction again, where you just raise the numerator by the desired exponent and the denomenator by the same desired exponent. (hope that helped - apologies for my english) Example 1: \[({1 \over 4}) ^2 = {1^2 \over 4^2} = {1 \over 16}\] Example2: \[({5 \over 4})^3 = {5^3 \over 4^3} = {125 \over 64}\]
Maybe this example helps: \[({3 \over 7})^3 = {3 \over 7} \times {3 \over 7} \times {3 \over 7} = {{3\times3\times3} \over {7\times7\times7}} = {3^3 \over 7^3} = {27 \over 343}\]
for the example above how would you write this as an integer
you can't
unless you round
an integer is an element of the set {...,-3,-2,-1,0,1,2,3,...}
i think i have got muddled i need to know how to raise 1/27 to the power of 3
(1/27)^3=1^3/27^3=1/(27*27*27)
so the integer is 1
no it is a rational number not an integer
it is 1/(27*27*27)
you can find the denominator's product by using a calculator
how do u get an integer is this done by x the 27 3 times
i have to leave this fraction cannot be written as an integer
ok thanks four your help
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