How do you find the differential of the integral cos^3(x) dx from -9ts to -5t+6s?

Question

anonymous · Answer

$$\int\limits_{-9ts}^{-5t+6s}\cos ^{3}(x) dx$$

amistre64 · Answer

ummmm......... i dont really know...

amistre64 · Answer

i spose its possible, just use those"equations" as the F(x) stuff in the end

amistre64 · Answer

you might want to go about "reducing" the integrand to an addition of sin and cos....maybe

amistre64 · Answer

cos cos^2

cos(1-sin^2)

cos(x)(1 - (1-cos(2x)/2)) ... along those lines eh?

dumbcow · Answer

yeah thats what i was going to say

amistre64 · Answer

well say it again then :)

dumbcow · Answer

integral of sin^2 is known as -x/2 + sincos/2
so you could use that

anonymous · Answer

Well I have notes and an example problem, but it doesnt really make sense. He has the differential of the integral e^-x^2 from a to b. He then takes partials. Fa = -e^a^2 and Fb = e^b^2. Then apparently the differential is -e^a^2 * da + e^b^2 * db. No sense.

anonymous · Answer

Don't worry about it, I just wondered if anyone could make sense out of it, but obviously my teacher is drunk. He wrote his own "textbook" in Mathematica and he didn't do a very good job.

dumbcow · Answer

are you still talking about integral of cos^3? anyway yeah there are no elementary functions to describe integral of e^(-x^2).