Question

is dere any easy way i can do standard form to vertex form?

Answer 1

probably; can you give an example?

Answer 2

f(x)= ax^2+bx+c to f(x)=a(x-h)^2+k

Answer 3

by completing the square

Answer 4

yeah... you can find the "x" value for the vertex by taking the -(middle#)/2(first#) that gives you your "h" value

plug that in for equation to ge the "y" value for it....which will be the "k"

does that make sense?

Answer 5

x^2 -12x + 45....

vertex = 12/2 = 6 = h

(6)^2 -12(6) +45 = k

Answer 6

y = (x+6)^2 + ...the # you find for k

Answer 7

x-6...... that is

Answer 8

f(x)=-4x^2-7x-2 ?? can u show me this one?

Answer 9

i gave you a bad "equation"...lol...but the steps are good

Answer 10

h = --7/2(-4) = 7/-8 = -7/8

Answer 11

k = -4(-7/8)^2 -7(-7/8) -2

Answer 12

k = 460/64 reduce as needed if I did it right in me head ;)

Answer 13

thats the "shortest" way I know...

Answer 14

im still kinda confuse but thanks :)