Question

I am trying to determine if the following is absolutely or conditionally convergent or divergent....

Answer 1

\[\sum_{n=1}^{\infty} (\sin 4n / 4^{n})\]

Answer 2

Ok. We can treat sin(4n) as (-1)^n. This is because the sine function varies between -1 and 1.

Answer 3

So that would give us [(-1)^n]/4^n. What kind of series does that look like?

Answer 4

so use the alternating series test?

Answer 5

Yes :)

Answer 6

ok, for some reason I thought I could only do that with cos

Answer 7

I don't know why

Answer 8

Nope works for both. Don't worry I get hiccups like that all the time. :)

Answer 9

thanks, pops!

Answer 10

you just helped me too pops I am doing an assignment on that as we speak

Answer 11

Your welcome :)