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How do you find the derivative of xe^(lnx^2)?
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\[xe^{\ln (2x^2)}\]
use the product rule then use chain rule
first write y=x(2x^2)=2x^3 so all we really need now is the power rule if y is written this way
y'=8x^2
e^ln(x^2) = x^2 x(x^2) = x^3 y' = 3x^2 ... if I read it right :)
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myin is right for the other option ;)
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