Question

Solve for k: ((16-2k)/3)^2+(2((16-2k)/3))+k=40

Answer 1

(256-64k+4k^2)/9 + (32-4k)/3 + k =40

Answer 2

then put them all over 9

Answer 3

(256-64k+4k^2 + 96-12k+9k-360)/9 = 0

Answer 4

Wait how'd you get the first step?

Answer 5

Never mind 16 squared?

Answer 6

I expanded the first part squared and multiplied the second part by 2

Answer 7

Do you know what to do from there?

Answer 8

i think so

Answer 9

just say so if you need more help

Answer 10

okay i got to -64k+4k^2-12k+9k=-352, how do i get all the k's alone?

Answer 11

you can group all the ks together and get 4k^2 + 67k +352 = 0

Answer 12

then use the quadratic equation with a=4, b=67, c=352

Answer 13

-67, sorry

Answer 14

whats the quadratic equation?

Answer 15

\[k=(-b \pm \sqrt{b ^{2}-4ac})/2a\]

Answer 16

gotcha!