Find the vertices, foci, and asymptotes of the hyperbola.
x^2 − 7y^2 = 8 can any one help me with this?

Question

myininaya · Answer

does this help? you can write the equation as (x-0)^2/8-(y-0)^2/(8/7)=1

anonymous · Answer

yes iv got all that. im just having trouble finding the asymptotes.

myininaya · Answer

myininaya · Answer

it says do sqrt(8)/sqrt(8/7) is the slope of the asymptote

myininaya · Answer

=sqrt(7)

anonymous · Answer

yes ive done that but i get a weird radical that i dont know how to reduce?...

myininaya · Answer

what is it?

anonymous · Answer

sqrt 65/7 / 2 sqrt 2

myininaya · Answer

sqrt(65/7)/[2sqrt(2)]?

anonymous · Answer

yes

myininaya · Answer

thats not the slope is it? what is that?

anonymous · Answer

the asymptotes

myininaya · Answer

I don't know about that.  i have to go though.  i'm sorry. if you want to simplify the above that you wrote, it is sqrt(65)/[2*sqrt(2)]

anonymous · Answer

thanks.

anonymous · Answer

sqrt(65)/[2*sqrt(2)]???

myininaya · Answer

oops lol

myininaya · Answer

sorry it was suppose to be 1/2  *  sqrt(65/14)

anonymous · Answer

ok let me try it.

myininaya · Answer

you have double fraction so you change to multiplication by flipping the second fraction

anonymous · Answer

1/2  *  sqrt(65/14)  is the final answer right?