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OpenStudy (anonymous):
what is the integral of 7/(t^3+3) from x to 1?
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OpenStudy (anonymous):
That's a very messy integral. You sure you typed that in correctly?
OpenStudy (anonymous):
do you mean:\[\int\limits_{x}^{1}2/(t^3+3)dx\]
? ^_^
OpenStudy (anonymous):
That doesn't make the integral any more simple. You could fill up several pages calculating that integral unless I'm missing something obvious.
OpenStudy (anonymous):
lol, calm down, let's just check ? :)
OpenStudy (anonymous):
Yes, i did mean what sstarica said
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OpenStudy (anonymous):
except the 2 is a 7
OpenStudy (amistre64):
dx ..... is that a typo.....should be "dt" right?
OpenStudy (anonymous):
LOL yeah, sorry >_<
OpenStudy (anonymous):
yes dt
OpenStudy (amistre64):
would splitting the variables help us?
dy/dt = 7/(t^3 +3)
dy/7 = dt/(t^3+3) ?? maybe not
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OpenStudy (anonymous):
figured it out it is just the original function
OpenStudy (amistre64):
.....thatd be a trick :)
OpenStudy (anonymous):
thank you!
OpenStudy (amistre64):
how you work that out?
OpenStudy (anonymous):
using the first part of the fundamental thm of calc
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OpenStudy (amistre64):
ohhh yeah ...the first part of the thing about that stuff.... yeah.... I was gonna do that but you know.... :)
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