what is the integral of 7/(t^3+3) from x to 1?
That's a very messy integral. You sure you typed that in correctly?
do you mean:\[\int\limits_{x}^{1}2/(t^3+3)dx\] ? ^_^
That doesn't make the integral any more simple. You could fill up several pages calculating that integral unless I'm missing something obvious.
lol, calm down, let's just check ? :)
Yes, i did mean what sstarica said
except the 2 is a 7
dx ..... is that a typo.....should be "dt" right?
LOL yeah, sorry >_<
yes dt
would splitting the variables help us? dy/dt = 7/(t^3 +3) dy/7 = dt/(t^3+3) ?? maybe not
figured it out it is just the original function
.....thatd be a trick :)
thank you!
how you work that out?
using the first part of the fundamental thm of calc
ohhh yeah ...the first part of the thing about that stuff.... yeah.... I was gonna do that but you know.... :)
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