FInd the indefinite integral using substitution. let u = 2x^2 + 3x + 9.
(4x + 3)/ (2x^2 + 3x + 9)^(7/3)dx.
can someone please give me the steps and answer . im in desperate need

Question

anonymous · Answer

du = (7/3)*(4x+3)^(4/3)

anonymous · Answer

Do you see that?

anonymous · Answer

Actually I take that back. Try [(7/3)(2x^2+3x+9)^(4/3)] * (4x+3) dx

anonymous · Answer

= du

anonymous · Answer

I got (-3/4)[(2x^2)+3x+9)^(-3/4)]+C

anonymous · Answer

Oh wait sorry. It's gettin close to bed time lol. Just ignore me. good grief

anonymous · Answer

you just have to take the derivative of 2x^2+3x+9 and you get du=4x+3 dx...then you can substitute for the numberator of the integrand...then you can take the integral and back substitute u=2x^2+3x+9 after that.

anonymous · Answer

numerator*

anonymous · Answer

$$\int\limits_{?}^{?}( u^(-7/3) du$$

anonymous · Answer

you can then take the integral of that

anonymous · Answer

and then back substitute u to get the answer